tensorflow::ops::InplaceUpdate

#include <array_ops.h>

Updates specified rows 'i' with values 'v'.

Summary

Computes x[i, :] = v; return x.

Originally this function is mutative however for compilation we make this operation create / operate on a copy of x.

Arguments:

  • scope: A Scope object
  • x: A tensor of type T.
  • i: A vector. Indices into the left-most dimension of x.
  • v: A Tensor of type T. Same dimension sizes as x except the first dimension, which must be the same as i's size.

Returns:

  • Output: A Tensor of type T. An alias of x. The content of y is undefined if there are duplicates in i.
Constructors and Destructors
InplaceUpdate(const ::tensorflow::Scope & scope, ::tensorflow::Input x, ::tensorflow::Input i, ::tensorflow::Input v)
Public attributes
operation
y
Public functions
node() const
::tensorflow::Node *
operator::tensorflow::Input() const
operator::tensorflow::Output() const

Public attributes

operation

Operation operation

y

::tensorflow::Output y

Public functions

InplaceUpdate

 InplaceUpdate(
  const ::tensorflow::Scope & scope,
  ::tensorflow::Input x,
  ::tensorflow::Input i,
  ::tensorflow::Input v
)

node

::tensorflow::Node * node() const 

operator::tensorflow::Input

operator::tensorflow::Input() const 

operator::tensorflow::Output

operator::tensorflow::Output() const 

© 2020 The TensorFlow Authors. All rights reserved.
Licensed under the Creative Commons Attribution License 4.0.
Code samples licensed under the Apache 2.0 License.
https://www.tensorflow.org/versions/r2.4/api_docs/cc/class/tensorflow/ops/inplace-update