Set.prototype.delete()

The delete() method removes a specified value from a Set object, if it is in the set.

Syntax

delete(value)

Parameters

value

The value to remove from mySet.

Return value

Returns true if value was already in mySet; otherwise false.

Examples

Using the delete() method

const mySet = new Set();
mySet.add('foo');

mySet.delete('bar'); // Returns false. No "bar" element found to be deleted.
mySet.delete('foo'); // Returns true. Successfully removed.

mySet.has('foo');    // Returns false. The "foo" element is no longer present.

Let's checkout below how to delete an Object from a Set.

const setObj = new Set();   // Create a new set.

setObj.add({x: 10, y: 20}); // Add object in the set.

setObj.add({x: 20, y: 30}); // Add object in the set.

// Delete any point with `x > 10`.
setObj.forEach(function(point){
  if (point.x > 10){
    setObj.delete(point)
  }
})

Specifications

Browser compatibility

Desktop Mobile
Chrome Edge Firefox Internet Explorer Opera Safari WebView Android Chrome Android Firefox for Android Opera Android Safari on IOS Samsung Internet
delete
38
12
13
11
25
8
38
38
14
25
8
3.0

See also

© 2005–2021 MDN contributors.
Licensed under the Creative Commons Attribution-ShareAlike License v2.5 or later.
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Set/delete