pandas.TimedeltaIndex.get_loc
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TimedeltaIndex.get_loc(key, method=None, tolerance=None)[source]
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Get integer location for requested label Returns: loc : int 
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Licensed under the 3-clause BSD License.
    https://pandas.pydata.org/pandas-docs/version/0.20.3/generated/pandas.TimedeltaIndex.get_loc.html