std::chrono::year_month_day_last::operator+=, std::chrono::year_month_day_last::operator-=
| constexpr std::chrono::year_month_day_last& operator+=(const std::chrono::years& dy) const noexcept; | (1) | (since C++20) | 
| constexpr std::chrono::year_month_day_last& operator+=(const std::chrono::months& dm) const noexcept; | (2) | (since C++20) | 
| constexpr std::chrono::year_month_day_last& operator-=(const std::chrono::years& dy) const noexcept; | (3) | (since C++20) | 
| constexpr std::chrono::year_month_day_last& operator-=(const std::chrono::months& dm) const noexcept; | (4) | (since C++20) | 
Modifies the time point *this represents by the duration dy or dm.
1) Equivalent to 
 *this = *this + dy;
2) Equivalent to 
 *this = *this + dm;
3) Equivalent to 
 *this = *this - dy;
4) Equivalent to 
 *this = *this - dm;
Notes
Durations that are convertible to std::chrono::months, but not std::chrono::years, can be directly added to or subtracted from a year_month_day_last. Durations convertible to std::chrono::years cannot because such durations are also convertible to std::chrono::months, resulting in an ambiguity:
using namespace std::chrono;
 
using decades = duration<int, std::ratio_multiply<std::ratio<10>, years::period>>;
using kilomonths = duration<int, std::ratio_multiply<std::kilo, months::period>>;
 
auto ymdl = 2001y/April/last;
ymdl += decades{1}; // error, ambiguous
ymdl += kilomonths{1}; // OKSee also
| adds or subtracts a year_month_day_lastand some number of years or months(public member function) | 
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