tf.sparse.segment_sqrt_n
| View source on GitHub |
Computes the sum along sparse segments of a tensor divided by the sqrt(N).
tf.sparse.segment_sqrt_n(
data, indices, segment_ids, num_segments=None, name=None
)
Read the section on segmentation for an explanation of segments.
Like tf.sparse.segment_mean, but instead of dividing by the size of the segment, N, divide by sqrt(N) instead.
| Args | |
|---|---|
data | A Tensor with data that will be assembled in the output. |
indices | A 1-D Tensor with indices into data. Has same rank as segment_ids. |
segment_ids | A 1-D Tensor with indices into the output Tensor. Values should be sorted and can be repeated. |
num_segments | An optional int32 scalar. Indicates the size of the output Tensor. |
name | A name for the operation (optional). |
| Returns | |
|---|---|
A tensor of the shape as data, except for dimension 0 which has size k, the number of segments specified via num_segments or inferred for the last element in segments_ids. |
© 2020 The TensorFlow Authors. All rights reserved.
Licensed under the Creative Commons Attribution License 3.0.
Code samples licensed under the Apache 2.0 License.
https://www.tensorflow.org/versions/r2.4/api_docs/python/tf/sparse/segment_sqrt_n