numpy.ma.allclose
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numpy.ma.allclose(a, b, masked_equal=True, rtol=1e-05, atol=1e-08)[source]
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Returns True if two arrays are element-wise equal within a tolerance. This function is equivalent to allcloseexcept that masked values are treated as equal (default) or unequal, depending on themasked_equalargument.Parameters: a, b : array_like Input arrays to compare. masked_equal : bool, optional Whether masked values in aandbare considered equal (True) or not (False). They are considered equal by default.rtol : float, optional Relative tolerance. The relative difference is equal to rtol * b. Default is 1e-5.atol : float, optional Absolute tolerance. The absolute difference is equal to atol. Default is 1e-8.Returns: y : bool Returns True if the two arrays are equal within the given tolerance, False otherwise. If either array contains NaN, then False is returned. NotesIf the following equation is element-wise True, then allclosereturns True:absolute(`a` - `b`) <= (`atol` + `rtol` * absolute(`b`)) Return True if all elements of aandbare equal subject to given tolerances.Examples>>> a = ma.array([1e10, 1e-7, 42.0], mask=[0, 0, 1]) >>> a masked_array(data = [10000000000.0 1e-07 --], mask = [False False True], fill_value = 1e+20) >>> b = ma.array([1e10, 1e-8, -42.0], mask=[0, 0, 1]) >>> ma.allclose(a, b) False>>> a = ma.array([1e10, 1e-8, 42.0], mask=[0, 0, 1]) >>> b = ma.array([1.00001e10, 1e-9, -42.0], mask=[0, 0, 1]) >>> ma.allclose(a, b) True >>> ma.allclose(a, b, masked_equal=False) False Masked values are not compared directly. >>> a = ma.array([1e10, 1e-8, 42.0], mask=[0, 0, 1]) >>> b = ma.array([1.00001e10, 1e-9, 42.0], mask=[0, 0, 1]) >>> ma.allclose(a, b) True >>> ma.allclose(a, b, masked_equal=False) False 
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